Differentiating trigonometric functions
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Quick questions to start.
- A1Last lesson[2 marks]
Differentiate .
Answer - A2Needed today[2 marks]
Given that and is acute, find the exact value of .
Answer - A3Needed today[3 marks]
Write as and use the chain rule to find .
Answer - A4Common slip[2 marks]
Sam writes that the derivative of is . Explain his mistake and give the correct derivative.
Example, then your turn
A-LevelYour teacher works through each example with you. Then try the one beside it.
Prove that .
- B1[4 marks]
Prove that .
Show that the derivative of is .
- B2[4 marks]
Given , find and the exact gradient of the curve at the point where .
Answer
Given , find .
- B3[5 marks]
The curve has equation , . Find an equation of the tangent to at the point where .
Answer
Given that , , find in terms of .
- B4[4 marks]
Given that , , show that .
Find the exact -coordinates of the stationary points of , .
- B5[5 marks]
The curve has equation , . Find the exact -coordinates of the stationary points of and decide the nature of each.
Answer
Practice
A-Level- C1[4 marks]
Tom differentiates and writes . Explain his mistake, then find the gradient of the curve at the point where .
Answer
- C2[5 marks]
The curve has equation , . Show that , and find an equation of the tangent to at the point where , in exact form.
Answer - C3[4 marks]
Given that , , show that .
- C4[5 marks]
Given , find in its simplest form.
Answer - C5[6 marks]
Find the exact coordinates of the stationary point on the curve , .
Answer
Exam-style questions
Edexcel exam style- D1
Kai says: "The derivative of is , because the derivative of is ."
Kai is wrong.
(a)[3 marks]Explain his mistake and find the correct derivative of .
Answer(b)[3 marks]Use the identity to check your answer, by differentiating .
(c)[3 marks]Find the exact gradient of the curve at the point where .
AnswerTotal for D1: 9 marks
- D2
The curve has equation , .
(a)[3 marks]Show that .
(b)[4 marks]Hence show that has no stationary points.
(c)[2 marks]Find an equation of the tangent to at the origin.
Answer(d)[2 marks]Find the exact gradient of at the point where .
AnswerTotal for D2: 11 marks - D3[6 marks]
Find an equation of the normal to the curve at the point where , in the form , where and are exact.
Answer - D4
The curve has equation , .
(a)[4 marks]Show that .
(b)[3 marks]Find an equation of the tangent to at the point where .
Answer(c)[2 marks]Explain why the gradient of is positive at every point.
Total for D4: 9 marks - D5
A straight rod touches the inside corner where a corridor m wide meets a corridor m wide at right angles, and its ends touch the two outer walls. When the rod makes an angle with the outer wall of the wider corridor, its length is , . The shortest such rod gives the longest rod that can be carried round the corner flat.
(a)[2 marks]Find .
Answer(b)[3 marks]Show that is stationary when .
(c)[2 marks]Find this value of , in radians to 3 significant figures.
Answer(d)[2 marks]Find the length of the longest rod that can be carried round the corner flat, to 3 significant figures.
Answer(e)[2 marks]Show that this value of gives the least value of .
Total for D5: 11 marks - D6
The curve has equation , .
(a)[4 marks]Show that .
(b)[3 marks]Find the least value of the gradient of C, and the exact value of x at which it occurs.
AnswerTotal for D6: 7 marks
Extension
StretchNo route is given. The hints are at the end of the sheet. Use one at a time.
- E1[9 marks]
The curve has equation , , where is a constant. Show that has a stationary point exactly when , that this stationary point is always a minimum, and that the least value of is .
Hint 1 · What to try
Differentiate, then write the derivative over the single denominator . When is the top zero?
Hint 2 · The first line
For which values of k does sin x equal minus k for an x strictly between minus a right angle and a right angle?
Hint 3 · The full method
At the stationary point . Find in terms of , then write over .
How did it go?
Colour one circle on each line.| Not yet | Nearly | Yes | |
|---|---|---|---|
| I can differentiate tan kx, sec kx, cosec kx and cot kx. | |||
| I can prove these results with the quotient rule or the chain rule. | |||
| I can combine them with the chain, product and quotient rules. | |||
| I can find dy/dx in terms of x when x is a trigonometric function of y. |
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